Viewed 11 times 1 $\begingroup$ Okay so the problem itself is really simple, If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23. If a box contains twenty-one coloured discs, composed of fifteen blue discs and six red discs, and two discs were taken at random, it can be seen that the probability of taking two blue discs, P(BB) = (15/21)×(14/20) = 1/2. The sum of these multiples is 23. Although mathematics will help you arrive at elegant and efficient methods, the use of a computer and … If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. Submissions. Project Euler solutions Introduction. Discussions. \$\begingroup\$ BTW it would be best to include the specification of the project Euler problem 1 in your question if you implemented the problem solution as stated in project euler. The sum of these multiples is . I'm learning C++ and currently doing Project Euler challenges. – Tangentially Perpendicular 15 mins ago May 3, 2011 Programming C++, Code, Project Euler Rian. If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. If we list all the natural numbers below that are multiples of or , we get and . The sum of these multiples is 23. Problem. The series, 1 1 + 2 2 + 3 3 + … + 10 10 = 10405071317.. Find the last ten digits of the series, 1 1 + 2 2 + 3 3 + … + 1000 1000.. Leaderboard. C++ solution to Project Euler Problem 1. Ask Question Asked today. The sum of these multiples is 23. Project Euler (projecteuler.net) is a series of challenging mathematical/computer programming problems that will require more than just mathematical insights to solve. This problem is a programming version of Problem 1 from projecteuler.net. I suppose that Euler_Project are for getting better at programming, I don't think you should handle answers as easily as you did. Project Euler #1: Multiples of 3 and 5. Solution Obvious solution. ... but it was the Project Euler forums that showed me the formula to do it. Make an attempt, then come back with specific questions about any difficulties you're having. Find the sum of all the multiples of 3 or 5 below 1000. Project Euler is a teaching resource. We won't just give you a solution - what would you learn if we did? A more mathematical way to solve the first problem in the project Euler archives. – Fabinout Jan 29 '14 at 16:24 Problem 48 of Project Euler has the nice and simple description. Project Euler Problem 1 Statement. The first challenge is the following. Since you have a generalized solution, you should provide your generalized specification of the problem. Problem 1: If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. Question 1: If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. 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